pKa Calculator

Choose the chemistry values you have to calculate pKa or Ka for an acid, buffer, or monoprotic weak-acid solution.

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How to use our pKa Calculator

  1. Choose what you know from your problem, lab notes, or reference table.
  2. Enter the values shown for that choice. Ka and concentrations must be greater than 0, and Ka accepts scientific notation such as 1.8e-5.
  3. Click Calculate to see the requested value first, followed by the related Ka or pKa and the equation used.
  4. Check the answer against the chemistry: a larger Ka should give a smaller pKa, and a buffer with more [A-] than [HA] should have a pKa below its pH.
Example inputs for pKa Calculator
Example inputs for pKa Calculator

Definitions

Ka: The acid dissociation constant. Under the same conditions, a larger Ka means more acid dissociation.

pKa: The negative base-10 logarithm of Ka. A larger pKa corresponds to a smaller Ka.

pH: A base-10 logarithmic measure related to hydrogen-ion concentration in a solution.

[A-]: The concentration of the conjugate base, in molarity (M).

[HA]: The concentration of the weak acid, in molarity (M).

Monoprotic weak acid: An acid that donates one hydrogen ion in the dissociation step being calculated.


Buffer balance by pH relative to pKaUsual buffer range is within 1 pH unit of pKa. At pH = pKa, [A-] and [HA] are equal.Buffer balance by pH relative to pKaUsual buffer range is within 1 pH unit of pKa.Acid favoredUsual rangeUsual rangeBase favored-2-1012pH minus pKa (pH units)
Buffer balance by pH relative to pKa
At pH = pKa, [A-] and [HA] are equal.

Common mistakes and quick fixes

Mistake: Entering 0 or a negative Ka.
Fix: Enter a finite Ka greater than 0. pKa cannot be calculated from zero because the base-10 logarithm of zero is undefined.

Mistake: Reversing the buffer ratio as [HA]/[A-].
Fix: Enter conjugate base [A-] and weak acid [HA] in their matching fields. The buffer equation uses [A-]/[HA].

Mistake: Using starting concentrations instead of the stated buffer concentrations after a reaction.
Fix: Use the weak-acid and conjugate-base concentrations for the buffer state described in the problem.

Mistake: Using the measured weak-acid method for a solution with an added conjugate base.
Fix: Choose the buffer method when both [A-] and [HA] are present as a buffer pair.

Mistake: Entering an initial weak-acid concentration that is no greater than the hydrogen-ion concentration from pH.
Fix: Enter an initial [HA] greater than 10 raised to the negative pH. Otherwise the calculated undissociated-acid concentration is zero or negative.


Limitations & Key Assumptions / Boundary Conditions

  • Ka and pKa can change with temperature, ionic strength, and other solution conditions, so a measured value can differ from a table value.
  • The buffer method uses the Henderson-Hasselbalch concentration ratio approximation and assumes both weak acid and conjugate base are present.
  • The measured weak-acid method assumes a monoprotic weak acid, no added conjugate-base buffer pair, and hydrogen ions supplied mainly by that acid.
  • For the measured weak-acid method, initial [HA] must be greater than the hydrogen-ion concentration calculated from pH.
  • For a polyprotic acid, use the Ka or pKa for the specific dissociation step named in the problem.
  • A buffer calculation is still defined when [A-]/[HA] is outside 0.1 to 10, but pH is then more than about 1 unit from pKa and the buffer is less balanced.

Methodology

Calculation method

The calculator uses base-10 logarithms and applies only the equation that matches the selected inputs.

pKa = -log10(Ka)

When pKa is known instead, it calculates Ka with:

Ka = 10^(-pKa)

For a buffer, it calculates the conjugate-base-to-acid ratio in that order, then rearranges the Henderson-Hasselbalch equation.

ratio = [A-] / [HA]

pKa = pH - log10(ratio)

For a measured solution containing only a monoprotic weak acid, it first converts pH to hydrogen-ion concentration and then calculates Ka.

[H+] = 10^(-pH)

Ka = [H+]^2 / (initial [HA] - [H+])

pKa = -log10(Ka)

Worked example

For a buffer with pH 5.20, [A-] = 0.20 M, and [HA] = 0.10 M, the ratio is 2. The pKa is 5.20 - log10(2) = 4.89897, or about 4.899. Converting that pKa gives Ka = 1.2619e-5.